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What is the area of the solution region formed by (x\geq 2), (y\geq 0), (x+y\leq 9), and (2x+y\leq 12)?असमानताओं (x\geq 2), (y\geq 0), (x+y\leq 9), (2x+y\leq 12) से बने हल-क्षेत्र का क्षेत्रफल कितना है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (20) square units(20) वर्ग इकाई
The vertices are ((2,0)), ((6,0)), ((3,6)), and ((2,7)). Using the shoelace method or splitting into parts gives area (20).शीर्ष ((2,0)), ((6,0)), ((3,6)), ((2,7)) हैं। शूलेस विधि या भागों में बांटकर क्षेत्रफल (20) मिलता है।
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