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What are the vertices of the solution region of \(x\geq 0\), \(y\geq 0\), \(2x+y\leq 12\), and \(x+3y\leq 15\)?असमानताओं \(x\geq 0\), \(y\geq 0\), \(2x+y\leq 12\), \(x+3y\leq 15\) के हल-क्षेत्र के शीर्ष कौन से हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((0,0)), ((6,0)), \(\left(\frac{21}{5},\frac{18}{5}\right)\), ((0,5))((0,0)), ((6,0)), \(\left(\frac{21}{5},\frac{18}{5}\right)\), ((0,5))
The intersection of the two slant lines is \(\left(\frac{21}{5},\frac{18}{5}\right)\). Use valid intercepts on the axes to choose all polygon corners.दोनों तिरछी रेखाओं का प्रतिच्छेद \(\left(\frac{21}{5},\frac{18}{5}\right)\) है। अक्षों पर वैध अवरोध लेकर पूरे बहुभुज के कोने चुनें।
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