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In the region formed by (2x+y\leq 16), (x+4y\leq 20), (x\geq 1), and (y\geq 0), what is the intersection of the slant lines?असमानताओं (2x+y\leq 16), (x+4y\leq 20), (x\geq 1), (y\geq 0) से बने क्षेत्र में तिरछी रेखाओं का प्रतिच्छेद कौन सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \((\left(\frac{44}{7},\frac{24}{7}\right)) / (\left(\frac{44}{7},\frac{24}{7}\right))\)\((\left(\frac{44}{7},\frac{24}{7}\right)) / (\left(\frac{44}{7},\frac{24}{7}\right))\)
Solving the two equations gives (x=\frac{44}{7}) and (y=\frac{24}{7}). Always test the intersection in all inequalities afterward.दोनों समीकरणों को हल करने पर (x=\frac{44}{7}) और (y=\frac{24}{7}) मिलता है। प्रतिच्छेद को बाद में सभी असमानताओं से जरूर जांचें।
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