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Class 11MathematicsLinear InequalitiesGraphical solution of linear inequalities in two variablesExpert
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What is the common solution region of (2x-y\leq 4) and (2x-y>8)?

Answer and explanation

Correct answer: Empty region

The same expression (2x-y) cannot be at most (4) and greater than (8) at the same time. Check contradictions before drawing the graph.

Related tags

Linear InequalitiesNo SolutionParallel BoundariesExpertGraphical Solution Of Linear Inequalities In Two VariablesMathematicsClass 11 Mcq
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10 more MCQs
  1. 1Which statement correctly means x∈[1,4]?
  2. 2Which statement is always true about the solution region of a system of linear inequalities in two variables?
  3. 3In the graph of the inequality (x+y\leq 4), where will the point ((0,0)) lie?
  4. 4For the inequality (y> x+1), how is the boundary line drawn?
  5. 5Which is the solution region of (y\leq 3)?
  6. 6What region does the graph of (x> -2) represent?
  7. 7What conclusion is obtained by testing ((0,0)) in (2x+y\geq 6)?
  8. 8Which statement is correct for the boundary line of (x+y<5)?
  9. 9For the inequality (x+2y\leq 8) with boundary (x+2y=8), which point is in the solution region?
  10. 10Will the boundary line be included in the graph of (y\geq -1)?
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