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Which is the solution region of (x\leq 4), (y\leq 3), (x+y\geq 5), (x\geq 0), (y\geq 0)?

Answer and explanation

Correct answer: Triangle with vertices ((2,3)), ((4,1)), ((4,3))

From the rectangle (0\leq x\leq 4), (0\leq y\leq 3), the part above (x+y=5) remains. Its vertices are ((2,3)), ((4,1)), and ((4,3)).

Related tags

Linear InequalitiesTriangleRectangle ClippingVerticesGraphical Solution Of Linear Inequalities In Two VariablesMathematicsClass 11 Mcq

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