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For the solution region of \(x+3y\leq 12\), \(2x+y\leq 10\), \(x\geq 0\), \(y\geq 0\), what is the intersection of the two slant boundaries?असमानताओं \(x+3y\leq 12\), \(2x+y\leq 10\), \(x\geq 0\), \(y\geq 0\) के हल-क्षेत्र में दोनों तिरछी सीमाओं का प्रतिच्छेद कौन सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\left(\frac{18}{5},\frac{14}{5}\right)\)\(\left(\frac{18}{5},\frac{14}{5}\right)\)
Solving the two equations gives \(x=\frac{18}{5}\) and \(y=\frac{14}{5}\). This is the inner corner on the graph.दोनों समीकरण हल करने पर \(x=\frac{18}{5}\) और \(y=\frac{14}{5}\) मिलता है। ग्राफ में यही आंतरिक कोना है।
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