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In the first quadrant, what is the common vertex of the two slant boundaries in the solution region of \(x+2y\le 16\), \(2x+y\le 14\), \(x\ge 0\), \(y\ge 0\)?प्रथम चतुर्थांश में असमानताओं \(x+2y\le 16\), \(2x+y\le 14\), \(x\ge 0\), \(y\ge 0\) से बने हल क्षेत्र में दोनों तिरछी सीमाओं का साझा शीर्ष कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\left(\frac{22}{3},\frac{13}{3}\right)\)\(\left(\frac{22}{3},\frac{13}{3}\right)\)
Solving \(x+2y=16\) and \(2x+y=14\) together gives \(\left(\frac{22}{3},\frac{13}{3}\right)\). In a graph, always check key vertices from boundary intersections.रेखाओं \(x+2y=16\) और \(2x+y=14\) को साथ हल करने पर \(\left(\frac{22}{3},\frac{13}{3}\right)\) मिलता है। ग्राफ में मुख्य शीर्ष हमेशा सीमा रेखाओं के प्रतिच्छेद से जांचें।
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