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In the first quadrant, what is the intersection of the boundaries \(x+4y\le 20\) and \(3x+y\le 18\)?प्रथम चतुर्थांश में \(x+4y\le 20\) और \(3x+y\le 18\) की सीमाओं का कटान कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\left(\frac{52}{11},\frac{42}{11}\right)\)\(\left(\frac{52}{11},\frac{42}{11}\right)\)
Solving \(x+4y=20\) and \(3x+y=18\) gives \(\left(\frac{52}{11},\frac{42}{11}\right)\). Do not avoid fractions when finding exact vertices.\(x+4y=20\) और \(3x+y=18\) हल करने पर \(\left(\frac{52}{11},\frac{42}{11}\right)\) मिलता है। सटीक शीर्ष के लिए भिन्नों से डरें नहीं।
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