0 reads0 ratings0 helpful
In the first-quadrant solution of \(x+2y\le 8\), \(2x+y\le 8\), where will the maximum value of (x+y) occur?प्रथम चतुर्थांश में \(x+2y\le 8\), \(2x+y\le 8\) के हल क्षेत्र में (x+y) का अधिकतम मान कहां मिलेगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\left(\frac{8}{3},\frac{8}{3}\right)\)\(\left(\frac{8}{3},\frac{8}{3}\right)\)
The intersection is \(\left(\frac{8}{3},\frac{8}{3}\right)\), where \(x+y=\frac{16}{3}\) is maximum. A linear expression attains its extreme value at a vertex.रेखाओं का प्रतिच्छेद \(\left(\frac{8}{3},\frac{8}{3}\right)\) है और वहां \(x+y=\frac{16}{3}\) अधिकतम है। रैखिक व्यंजक का चरम मान किसी शीर्ष पर मिलता है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
