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In the first quadrant, what is the intersection of the shared boundaries \(x+2y\le 10\), \(3x+y\le 12\)?प्रथम चतुर्थांश में \(x+2y\le 10\), \(3x+y\le 12\) की साझा सीमा का प्रतिच्छेद कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\left(\frac{14}{5},\frac{18}{5}\right)\)\(\left(\frac{14}{5},\frac{18}{5}\right)\)
Solving \(x+2y=10\) and \(3x+y=12\) gives \(\left(\frac{14}{5},\frac{18}{5}\right)\). Fractional vertices are also valid in graphs.रेखाओं \(x+2y=10\) और \(3x+y=12\) को हल करने पर \(\left(\frac{14}{5},\frac{18}{5}\right)\) मिलता है। भिन्न वाले शीर्ष भी ग्राफ में मान्य होते हैं।
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