0 reads0 ratings0 helpful
What is the area of the triangle formed by (x+3y\le 9) in the first quadrant?प्रथम चतुर्थांश में (x+3y\le 9) से बने त्रिभुज का क्षेत्रफल क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{27}{2})(\frac{27}{2})
The intercepts are ((9,0)) and ((0,3)), so area is (\frac{1}{2}\times 9\times 3=\frac{27}{2}). For an axial triangle, use intercepts as base and height.अवरोध ((9,0)) और ((0,3)) हैं, इसलिए क्षेत्रफल (\frac{1}{2}\times 9\times 3=\frac{27}{2})। अक्षीय त्रिभुज में अवरोधों को आधार और ऊंचाई लें।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
