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What are the vertices of the solution region of (x\leq 4), (y\leq 4), (x+y\geq 6), (x\geq 0), (y\geq 0)?

Answer and explanation

Correct answer: ((2,4)), ((4,2)), ((4,4))

Inside the square (0\leq x\leq 4), (0\leq y\leq 4), the condition (x+y\geq 6) leaves the upper-right triangle. Exam tip: Draw the larger region first and then cut it.

Related tags

Linear InequalitiesVerticesSquare CutClass 11Graphical Solution Of Linear Inequalities In Two VariablesMathematicsClass 11 Mcq

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