0 reads0 ratings0 helpful
What are the vertices of the solution region of (3x+y\leq 6), (x-y\geq 0), (y\geq 0)?तंत्र (3x+y\leq 6), (x-y\geq 0), (y\geq 0) के हल क्षेत्र के शीर्ष कौन-से हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((0,0)), ((2,0)), ((\frac{3}{2},\frac{3}{2}))((0,0)), ((2,0)), ((\frac{3}{2},\frac{3}{2}))
The condition (x-y\geq 0) gives (y\leq x), and its intersection with (3x+y=6) is ((\frac{3}{2},\frac{3}{2})). Exam tip: Reading the region is easier after rewriting inequalities.(x-y\geq 0) से (y\leq x) और (3x+y=6) से प्रतिच्छेद ((\frac{3}{2},\frac{3}{2})) मिलता है। परीक्षा सुझाव: बदले हुए रूप में क्षेत्र पढ़ना आसान होता है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
