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In the common first-quadrant region of (2x+y\leq 8), (x+2y\leq 8), what is the maximum value of (x+y)?

Answer and explanation

Correct answer: (\frac{16}{3})

The two boundary lines meet at ((\frac{8}{3},\frac{8}{3})), where (x+y=\frac{16}{3}). Exam tip: A linear expression usually attains its extreme at a vertex.

Related tags

Linear InequalitiesMaximum ValueVerticesClass 11Graphical Solution Of Linear Inequalities In Two VariablesMathematicsClass 11 Mcq

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