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What are the vertices of the solution region of (x-y\leq 0), (x+y\leq 4), (x\geq 0)?

Answer and explanation

Correct answer: ((0,0)), ((0,4)), ((2,2))

The condition (x-y\leq 0) gives (y\geq x), and together with (x+y\leq 4) these form the triangle. Exam tip: Test every vertex in all inequalities.

Related tags

Linear InequalitiesVerticesCommon RegionClass 11Graphical Solution Of Linear Inequalities In Two VariablesMathematicsClass 11 Mcq

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