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In the first quadrant, what is the solution region of (3x+2y\geq 12)?

Answer and explanation

Correct answer: Unbounded part above the line with boundary

The origin gives (0\geq 12), which is false, so the side away from the origin is chosen. Exam tip: Always combine the region with the axes in the first quadrant.

Related tags

Linear InequalitiesFirst QuadrantUnbounded RegionClass 11Graphical Solution Of Linear Inequalities In Two VariablesMathematicsClass 11 Mcq

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