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In the first quadrant, what type of common solution is formed by (x+2y\ge6) and (2x+y\ge6)?

Answer and explanation

Correct answer: Unbounded region

Both inequalities select regions above the boundary lines, and the common region extends indefinitely. Conditions with (\ge) can often create an unbounded region.

Related tags

Linear InequalitiesGraphical SolutionClass 11Graphical Solution Of Linear Inequalities In Two VariablesMathematicsClass 11 Mcq

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