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If \(2x+y\le14\), \(x+2y\le14\), \(x\ge0\), \(y\ge0\), which vertex is where the two slant lines meet?यदि \(2x+y\le14\), \(x+2y\le14\), \(x\ge0\), \(y\ge0\) हैं, तो हल क्षेत्र का वह शीर्ष कौन सा है जहां दोनों तिरछी रेखाएं मिलती हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \( \left(\frac{14}{3},\frac{14}{3}\right) \)\( \left(\frac{14}{3},\frac{14}{3}\right) \)
The two equations give \(x=y\) and \(3x=14\), so the vertex is \( \left(\frac{14}{3},\frac{14}{3}\right) \). Symmetric boundaries can quickly give \(x=y\).दोनों समीकरणों से \(x=y\) और \(3x=14\), इसलिए शीर्ष \( \left(\frac{14}{3},\frac{14}{3}\right) \) है। सममित सीमाओं में \(x=y\) जल्दी मिल सकता है।
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