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What is the nature of the solution region for (x\le6), (y\le5), (x+y\ge4), (x\ge0), (y\ge0)?व्यवस्था (x\le6), (y\le5), (x+y\ge4), (x\ge0), (y\ge0) का हल क्षेत्र कैसा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Boundedसीमित
The conditions (0\le x\le6) and (0\le y\le5) restrict the region inside a rectangle. The inequality (x+y\ge4) only cuts off one corner.(0\le x\le6) और (0\le y\le5) क्षेत्र को आयत में सीमित करते हैं। (x+y\ge4) केवल उसका एक कोना काटता है।
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