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Class 11MathematicsLinear InequalitiesGraphical solution of linear inequalities in two variablesHard
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If the boundary line is (3x+4y=24) and the solution is (3x+4y>24), on which side is ( (0,0) )?

Answer and explanation

Correct answer: On the opposite side of the solution region

At the origin, (0>24) is false, so the side containing the origin is not the solution. If the test point fails, shade the other side.

Related tags

Linear InequalitiesGraphical SolutionClass 11Graphical Solution Of Linear Inequalities In Two VariablesMathematicsClass 11 Mcq
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10 more MCQs
  1. 1Which statement correctly means x∈[1,4]?
  2. 2Which statement is always true about the solution region of a system of linear inequalities in two variables?
  3. 3In the graph of the inequality (x+y\leq 4), where will the point ((0,0)) lie?
  4. 4For the inequality (y> x+1), how is the boundary line drawn?
  5. 5Which is the solution region of (y\leq 3)?
  6. 6What region does the graph of (x> -2) represent?
  7. 7What conclusion is obtained by testing ((0,0)) in (2x+y\geq 6)?
  8. 8Which statement is correct for the boundary line of (x+y<5)?
  9. 9For the inequality (x+2y\leq 8) with boundary (x+2y=8), which point is in the solution region?
  10. 10Will the boundary line be included in the graph of (y\geq -1)?
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