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Which is the correct half-plane for the inequality (3x-2y \ge 6)?असमानता (3x-2y \ge 6) का सही अर्ध-तल कौन सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (y \le \frac{3x-6}{2})(y \le \frac{3x-6}{2})
From (3x-2y \ge 6), we get (y \le \frac{3x-6}{2}). When dividing by a negative number, the inequality sign reverses.(3x-2y \ge 6) से (y \le \frac{3x-6}{2}) मिलता है। ऋणात्मक संख्या से भाग देते समय असमानता का चिन्ह बदलता है।
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