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If \(x \ge 0\), \(y \ge 0\), \(x+2y \le 14\), and \(3x+y \le 18\), what is the intersection point of the two slant boundary lines?यदि \(x \ge 0\), \(y \ge 0\), \(x+2y \le 14\) और \(3x+y \le 18\) हों तो दोनों तिरछी सीमा रेखाओं का प्रतिच्छेद बिंदु कौन सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\left(\frac{22}{5},\frac{24}{5}\right)\)\(\left(\frac{22}{5},\frac{24}{5}\right)\)
Solving \(x+2y=14\) and \(3x+y=18\) gives \(x=\frac{22}{5}\), \(y=\frac{24}{5}\). In a graph, always find the intersection of slant boundaries separately.\(x+2y=14\) और \(3x+y=18\) हल करने पर \(x=\frac{22}{5}\), \(y=\frac{24}{5}\) मिलता है। ग्राफ में तिरछी सीमाओं का प्रतिच्छेद अलग से जरूर निकालें।
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