Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

How many vertices are in the solution region of \(x \ge 0\), \(y \ge 0\), \(2x+y \le 8\), and \(x+2y \le 8\)?

Answer and explanation

Correct answer: (4)

The vertices are ((0,0)), ((4,0)), \(\left(\frac{8}{3},\frac{8}{3}\right)\), and ((0,4)). List all valid corners in order.

Related tags

VerticesQuadrilateralFeasible RegionGraphical Solution Of Linear Inequalities In Two VariablesLinear InequalitiesMathematicsClass 11 Mcq

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Add Muft Shiksha to your Home Screen

In Safari, tap Share, then Add to Home Screen.