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With \(x+2y \le 8\), \(2x+y \le 8\), \(x \ge 0\), and \(y \ge 0\), which vertex is formed by the two slant boundary lines?असमानताओं \(x+2y \le 8\) और \(2x+y \le 8\) के साथ \(x \ge 0\), \(y \ge 0\) होने पर कौन सा शीर्ष सामान्य सीमा रेखाओं से बनता है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\left(\frac{8}{3},\frac{8}{3}\right)\)\(\left(\frac{8}{3},\frac{8}{3}\right)\)
Subtracting the two lines gives \(x=y\), then \(3x=8\), so \(x=y=\frac{8}{3}\). Find the intersection of slant boundaries separately.दोनों रेखाओं को घटाने पर \(x=y\), फिर \(3x=8\) से \(x=y=\frac{8}{3}\)। तिरछी सीमाओं का प्रतिच्छेद अलग से निकालें।
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