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What is the area of the region formed by (x\ge 1), (y\ge 0), (x+y\le 5), and (x\le 4)?असमानताओं (x\ge 1), (y\ge 0), (x+y\le 5), (x\le 4) से बने क्षेत्र का क्षेत्रफल क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{15}{2}) square units(\frac{15}{2}) वर्ग इकाई
The vertices are ((1,0)), ((4,0)), ((4,1)), and ((1,4)). With parallel sides (4) and (1) and distance (3), the area is (\frac{1}{2}(4+1)3=\frac{15}{2}).क्षेत्र के शीर्ष ((1,0)), ((4,0)), ((4,1)), ((1,4)) हैं। समांतर भुजाओं (4) और (1) तथा दूरी (3) से क्षेत्रफल (\frac{1}{2}(4+1)3=\frac{15}{2}) है।
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