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What is the \(x\)-intercept of the triangle formed by \(x\ge 0\), \(y\ge 0\), and \(x+3y\le 9\)?असमानताओं \(x\ge 0\), \(y\ge 0\), \(x+3y\le 9\) से बने त्रिभुज का \(x\)-अवरोध कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \((9,0)\)\((9,0)\)
To find the \(x\)-intercept, put \(y=0\). The boundary line \(x+3y=9\) then gives \(x=9\). Therefore, the point on the \(x\)-axis is \((9,0)\). \((0,3)\) is the \(y\)-intercept, not the \(x\)-intercept. Exam tip: for an \(x\)-intercept, always set \(y=0\).\(x\)-अवरोध ज्ञात करने के लिए \(y=0\) रखते हैं। तब सीमा रेखा \(x+3y=9\) से \(x=9\) प्राप्त होता है। अतः \(x\)-अक्ष पर बिंदु \((9,0)\) है। \((0,3)\) \(y\)-अवरोध है, \(x\)-अवरोध नहीं। परीक्षा टिप: \(x\)-अवरोध के लिए हमेशा \(y=0\) रखें।
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