Which point on the line \(x+2y=10\) is included in the solution of \(x+2y\le 10\)?

Correct answer: \((4,3)\)

For \((4,3)\), \(x+2y=4+2(3)=10\), so the point lies on the line \(x+2y=10\). Since the inequality uses \(\le\), every point on the boundary line is included in the solution region. For \((1,4)\), the value is \(9\), so it satisfies the inequality but does not lie on the given line. Exam tip: Include the boundary line whenever the sign is \(\le\) or \(\ge\).