Which point truly lies in the solution region of x + 2y > 8?

Correct answer: (2, 4)

The governing concept is testing points in a two-variable linear inequality. A point belongs to the solution region only when its coordinates make the inequality true. Because the sign is strict, the expression must be greater than 8; equality is not enough. For A, 0 + 2(4) = 8, so it lies on the boundary and is excluded. For B, 5 + 2(1) = 7, and for C, 3 + 2(1) = 5; both values are less than 8. For D, 2 + 2(4) = 10, and 10 > 8. Thus D satisfies the inequality and is the only valid point. The strict sign also explains why the boundary point A is not accepted.