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What is the (y)-intercept of (3x+y=15)?रेखा (3x+y=15) के लिए (y)-अवरोध क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(15\)\(15\)
To find the \(y\)-intercept, put \(x=0\). Then \(3(0)+y=15\), so \(y=15\). Hence, the line meets the \(y\)-axis at \((0,15)\), and its \(y\)-intercept is \(15\). The value \(5\) is the \(x\)-intercept, obtained by putting \(y=0\). Exam tip: for a \(y\)-intercept, always set \(x=0\).\(y\)-अवरोध ज्ञात करने के लिए \(x=0\) रखें। तब \(3(0)+y=15\), इसलिए \(y=15\) मिलता है। अतः रेखा \(y\)-अक्ष को \((0,15)\) पर काटती है और \(y\)-अवरोध \(15\) है। \(5\), \(x\)-अवरोध है, क्योंकि \(y=0\) रखने पर \(x=5\) मिलता है। परीक्षा टिप: \(y\)-अवरोध के लिए हमेशा \(x=0\) रखें।
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