Where is the point \((1,3)\) for \(y\leq -2x+6\)?

Correct answer: in the solution region

For the point \((1,3)\), substitute \(x=1\) and \(y=3\): \(3\leq -2(1)+6\), i.e. \(3\leq 4\), which is true. Hence, the point lies in the solution region of the inequality. It is not on the boundary line because \(3\neq 4\). Exam tip: To test a point, substitute its \(x\)- and \(y\)-coordinates in the inequality and check whether the statement is true.