\(^{n}P_r\) से \(^{n}C_r\) छोटा क्यों होता है जब (r>1)?

Why is \(^{n}C_r\) smaller than \(^{n}P_r\) when (r>1)?

Explanation opens after your attempt
Correct Answer

A. क्योंकि combination में (r!) orders को एक ही selection माना जाता हैBecause in combination (r!) orders are treated as one selection

Step 1

Concept

Permutation counts many orders of the same group. In exams keep the difference between (P) and (C) clear when (r>1).

Step 2

Why this answer is correct

The correct answer is A. क्योंकि combination में (r!) orders को एक ही selection माना जाता है / Because in combination (r!) orders are treated as one selection. Permutation counts many orders of the same group. In exams keep the difference between (P) and (C) clear when (r>1).

Step 3

Exam Tip

Permutation एक ही group के कई orders गिनता है। परीक्षा में (r>1) पर (P) और (C) का अंतर साफ रखें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(^{n}P_r\) से \(^{n}C_r\) छोटा क्यों होता है जब (r>1)? / Why is \(^{n}C_r\) smaller than \(^{n}P_r\) when (r>1)?

Correct Answer: A. क्योंकि combination में (r!) orders को एक ही selection माना जाता है / Because in combination (r!) orders are treated as one selection. Explanation: Permutation एक ही group के कई orders गिनता है। परीक्षा में (r>1) पर (P) और (C) का अंतर साफ रखें। / Permutation counts many orders of the same group. In exams keep the difference between (P) and (C) clear when (r>1).

Which concept should I revise for this Mathematics MCQ?

Permutation counts many orders of the same group. In exams keep the difference between (P) and (C) clear when (r>1).

What exam hint can help solve this Mathematics question?

Permutation एक ही group के कई orders गिनता है। परीक्षा में (r>1) पर (P) और (C) का अंतर साफ रखें।