\(^{n}P_r\) से \(^{n}C_r\) छोटा क्यों होता है जब (r>1)?
Why is \(^{n}C_r\) smaller than \(^{n}P_r\) when (r>1)?
Explanation opens after your attempt
A. क्योंकि combination में (r!) orders को एक ही selection माना जाता हैBecause in combination (r!) orders are treated as one selection
Concept
Permutation counts many orders of the same group. In exams keep the difference between (P) and (C) clear when (r>1).
Why this answer is correct
The correct answer is A. क्योंकि combination में (r!) orders को एक ही selection माना जाता है / Because in combination (r!) orders are treated as one selection. Permutation counts many orders of the same group. In exams keep the difference between (P) and (C) clear when (r>1).
Exam Tip
Permutation एक ही group के कई orders गिनता है। परीक्षा में (r>1) पर (P) और (C) का अंतर साफ रखें।
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