\(^{n}C_r\) और \(^{n}C_{r-1}\) के बीच कौन-सा अनुपात सही है?

Which ratio between \(^{n}C_r\) and \(^{n}C_{r-1}\) is correct?

Explanation opens after your attempt
Correct Answer

B. \(\frac{^{n}C_r}{^{n}C_{r-1}}=\frac{n-r+1}{r}\)

Step 1

Concept

Simplifying the factorial formula gives the ratio \(\frac{n-r+1}{r}\). In exams ratio method is useful for adjacent combinations.

Step 2

Why this answer is correct

The correct answer is B. \(\frac{^{n}C_r}{^{n}C_{r-1}}=\frac{n-r+1}{r}\). Simplifying the factorial formula gives the ratio \(\frac{n-r+1}{r}\). In exams ratio method is useful for adjacent combinations.

Step 3

Exam Tip

Factorial formula से सरल करने पर अनुपात \(\frac{n-r+1}{r}\) मिलता है। परीक्षा में adjacent combinations में ratio method उपयोगी है।

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Mathematics Answer, Explanation and Revision Hints

\(^{n}C_r\) और \(^{n}C_{r-1}\) के बीच कौन-सा अनुपात सही है? / Which ratio between \(^{n}C_r\) and \(^{n}C_{r-1}\) is correct?

Correct Answer: B. \(\frac{^{n}C_r}{^{n}C_{r-1}}=\frac{n-r+1}{r}\). Explanation: Factorial formula से सरल करने पर अनुपात \(\frac{n-r+1}{r}\) मिलता है। परीक्षा में adjacent combinations में ratio method उपयोगी है। / Simplifying the factorial formula gives the ratio \(\frac{n-r+1}{r}\). In exams ratio method is useful for adjacent combinations.

Which concept should I revise for this Mathematics MCQ?

Simplifying the factorial formula gives the ratio \(\frac{n-r+1}{r}\). In exams ratio method is useful for adjacent combinations.

What exam hint can help solve this Mathematics question?

Factorial formula से सरल करने पर अनुपात \(\frac{n-r+1}{r}\) मिलता है। परीक्षा में adjacent combinations में ratio method उपयोगी है।