कौन सा बिंदु \(2x-y\le1\) की सीमा पर है लेकिन (2x-y<1) के हल में नहीं है?
Which point lies on the boundary of \(2x-y\le1\) but not in the solution of (2x-y<1)?
Explanation opens after your attempt
B. ( (2,3) )
Concept
At ( (2,3) ), (2x-y=1), so it lies on the boundary. Strict inequality (<) does not include boundary points.
Why this answer is correct
The correct answer is B. ( (2,3) ). At ( (2,3) ), (2x-y=1), so it lies on the boundary. Strict inequality (<) does not include boundary points.
Exam Tip
( (2,3) ) पर (2x-y=1), इसलिए यह सीमा पर है। सख्त असमानता (<) में सीमा बिंदु शामिल नहीं होते।
Login to save your score, XP, coins and progress.
