कौन सा बिंदु \(2x-y\le1\) की सीमा पर है लेकिन (2x-y<1) के हल में नहीं है?

Which point lies on the boundary of \(2x-y\le1\) but not in the solution of (2x-y<1)?

Explanation opens after your attempt
Correct Answer

B. ( (2,3) )

Step 1

Concept

At ( (2,3) ), (2x-y=1), so it lies on the boundary. Strict inequality (<) does not include boundary points.

Step 2

Why this answer is correct

The correct answer is B. ( (2,3) ). At ( (2,3) ), (2x-y=1), so it lies on the boundary. Strict inequality (<) does not include boundary points.

Step 3

Exam Tip

( (2,3) ) पर (2x-y=1), इसलिए यह सीमा पर है। सख्त असमानता (<) में सीमा बिंदु शामिल नहीं होते।

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कौन सा बिंदु \(2x-y\le1\) की सीमा पर है लेकिन (2x-y<1) के हल में नहीं है? / Which point lies on the boundary of \(2x-y\le1\) but not in the solution of (2x-y<1)?

Correct Answer: B. ( (2,3) ). Explanation: ( (2,3) ) पर (2x-y=1), इसलिए यह सीमा पर है। सख्त असमानता (<) में सीमा बिंदु शामिल नहीं होते। / At ( (2,3) ), (2x-y=1), so it lies on the boundary. Strict inequality (<) does not include boundary points.

Which concept should I revise for this Mathematics MCQ?

At ( (2,3) ), (2x-y=1), so it lies on the boundary. Strict inequality (<) does not include boundary points.

What exam hint can help solve this Mathematics question?

( (2,3) ) पर (2x-y=1), इसलिए यह सीमा पर है। सख्त असमानता (<) में सीमा बिंदु शामिल नहीं होते।