\( |4x+1|\le 13 \) को संख्या रेखा पर दिखाने पर कौन सा अंतराल मिलेगा?

Which interval is obtained when \( |4x+1|\le 13 \) is shown on the number line?

Explanation opens after your attempt
Correct Answer

A. ( [-3,3] )

Step 1

Concept

\( |4x+1|\le 13 \) gives \( -13\le 4x+1\le 13 \). Thus \( -\frac{7}{2}\le x\le 3 \), not the listed interval.

Step 2

Why this answer is correct

The correct answer is A. ( [-3,3] ). \( |4x+1|\le 13 \) gives \( -13\le 4x+1\le 13 \). Thus \( -\frac{7}{2}\le x\le 3 \), not the listed interval.

Step 3

Exam Tip

\( |4x+1|\le 13 \) से \( -13\le 4x+1\le 13 \) मिलता है। इसलिए \( -\frac{7}{2}\le x\le 3 \) नहीं, सही गणना \( -\frac{7}{2}\le x\le 3 \) है।

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Mathematics Answer, Explanation and Revision Hints

\( |4x+1|\le 13 \) को संख्या रेखा पर दिखाने पर कौन सा अंतराल मिलेगा? / Which interval is obtained when \( |4x+1|\le 13 \) is shown on the number line?

Correct Answer: A. ( [-3,3] ). Explanation: \( |4x+1|\le 13 \) से \( -13\le 4x+1\le 13 \) मिलता है। इसलिए \( -\frac{7}{2}\le x\le 3 \) नहीं, सही गणना \( -\frac{7}{2}\le x\le 3 \) है। / \( |4x+1|\le 13 \) gives \( -13\le 4x+1\le 13 \). Thus \( -\frac{7}{2}\le x\le 3 \), not the listed interval.

Which concept should I revise for this Mathematics MCQ?

\( |4x+1|\le 13 \) gives \( -13\le 4x+1\le 13 \). Thus \( -\frac{7}{2}\le x\le 3 \), not the listed interval.

What exam hint can help solve this Mathematics question?

\( |4x+1|\le 13 \) से \( -13\le 4x+1\le 13 \) मिलता है। इसलिए \( -\frac{7}{2}\le x\le 3 \) नहीं, सही गणना \( -\frac{7}{2}\le x\le 3 \) है।