सूत्र (^{n}C_r=\frac{n!}{r!(n-r)!}) किस विचार से प्राप्त होता है?
Which idea gives (^{n}C_r=\frac{n!}{r!(n-r)!})?
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Correct Answer
B. \(^{n}P_r\) को (r!) से भाग देनाDividing \(^{n}P_r\) by (r!)
Concept
In combination extra orders are removed from permutation. In exams write \(^{n}P_r\) and divide by (r!).
Why this answer is correct
The correct answer is B. \(^{n}P_r\) को (r!) से भाग देना / Dividing \(^{n}P_r\) by (r!). In combination extra orders are removed from permutation. In exams write \(^{n}P_r\) and divide by (r!).
Exam Tip
Combination में permutation से अतिरिक्त क्रम हटाए जाते हैं। परीक्षा में \(^{n}P_r\) लिखकर (r!) से भाग दें।
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