\(^{15}P_3\) को \(^{15}C_3\) से जोड़ने पर कौन-सा factor लगता है?

When connecting \(^{15}P_3\) with \(^{15}C_3\), which factor is used?

Explanation opens after your attempt
Correct Answer

A. (3!)

Step 1

Concept

First choose (3) objects and arrange them in (3!) ways. In exams remember \(^{n}P_3=^{n}C_3\cdot3!\).

Step 2

Why this answer is correct

The correct answer is A. (3!). First choose (3) objects and arrange them in (3!) ways. In exams remember \(^{n}P_3=^{n}C_3\cdot3!\).

Step 3

Exam Tip

पहले (3) वस्तुएं चुनकर उन्हें (3!) ways में arrange करते हैं। परीक्षा में \(^{n}P_3=^{n}C_3\cdot3!\) याद रखें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\(^{15}P_3\) को \(^{15}C_3\) से जोड़ने पर कौन-सा factor लगता है? / When connecting \(^{15}P_3\) with \(^{15}C_3\), which factor is used?

Correct Answer: A. (3!). Explanation: पहले (3) वस्तुएं चुनकर उन्हें (3!) ways में arrange करते हैं। परीक्षा में \(^{n}P_3=^{n}C_3\cdot3!\) याद रखें। / First choose (3) objects and arrange them in (3!) ways. In exams remember \(^{n}P_3=^{n}C_3\cdot3!\).

Which concept should I revise for this Mathematics MCQ?

First choose (3) objects and arrange them in (3!) ways. In exams remember \(^{n}P_3=^{n}C_3\cdot3!\).

What exam hint can help solve this Mathematics question?

पहले (3) वस्तुएं चुनकर उन्हें (3!) ways में arrange करते हैं। परीक्षा में \(^{n}P_3=^{n}C_3\cdot3!\) याद रखें।