असमानताओं \(x+y\ge 4\), \(x\ge 0\), \(y\ge 0\) का हल क्षेत्र कैसा है?
What type of solution region is given by \(x+y\ge 4\), \(x\ge 0\), and \(y\ge 0\)?
Explanation opens after your attempt
Correct Answer
B. असीमितunbounded
Concept
In the first quadrant, the region above (x+y=4) extends infinitely. Hence the region is unbounded.
Why this answer is correct
The correct answer is B. असीमित / unbounded. In the first quadrant, the region above (x+y=4) extends infinitely. Hence the region is unbounded.
Exam Tip
प्रथम चतुर्थांश में (x+y=4) के ऊपर का क्षेत्र अनंत तक जाता है। इसलिए क्षेत्र असीमित है।
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