संयुक्त असमानता \(-4<\frac{x+2}{3}\le2\) का हल कौन सा है?
What is the solution of the compound inequality \(-4<\frac{x+2}{3}\le2\)?
Explanation opens after your attempt
Correct Answer
A. \(-14<x\le4\)
Concept
Multiplying by positive (3) gives \(-12<x+2\le6\), so \(-14<x\le4\). In exams preserve open and closed signs separately.
Why this answer is correct
The correct answer is A. \(-14<x\le4\). Multiplying by positive (3) gives \(-12<x+2\le6\), so \(-14<x\le4\). In exams preserve open and closed signs separately.
Exam Tip
धनात्मक (3) से गुणा करने पर \(-12<x+2\le6\), इसलिए \(-14<x\le4\)। परीक्षा में खुले और बंद चिह्न अलग-अलग बनाए रखें।
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