संयुक्त असमानता \(-4<\frac{x+2}{3}\le2\) का हल कौन सा है?

What is the solution of the compound inequality \(-4<\frac{x+2}{3}\le2\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. \(-14<x\le4\)

Explanation

Simple Explanation

धनात्मक (3) से गुणा करने पर \(-12<x+2\le6\), इसलिए \(-14<x\le4\)। परीक्षा में खुले और बंद चिह्न अलग-अलग बनाए रखें। / Multiplying by positive (3) gives \(-12<x+2\le6\), so \(-14<x\le4\). In exams preserve open and closed signs separately.

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FAQs

Mathematics Answer, Explanation and Revision Hints

संयुक्त असमानता \(-4<\frac{x+2}{3}\le2\) का हल कौन सा है? / What is the solution of the compound inequality \(-4<\frac{x+2}{3}\le2\)?

Correct Answer: A. \(-14<x\le4\). Explanation: धनात्मक (3) से गुणा करने पर \(-12<x+2\le6\), इसलिए \(-14<x\le4\)। परीक्षा में खुले और बंद चिह्न अलग-अलग बनाए रखें। / Multiplying by positive (3) gives \(-12<x+2\le6\), so \(-14<x\le4\). In exams preserve open and closed signs separately.