संयुक्त असमानता (-2(3x-4)\le 5-x<2x+7) का हल क्या है?

What is the solution of the compound inequality (-2(3x-4)\le 5-x<2x+7)?

Explanation opens after your attempt
Correct Answer

B. \({x:x\ge \frac{3}{5}}\)

Step 1

Concept

Solving both parts separately gives \(x\ge \frac{3}{5}\) and \(x>-\frac{2}{3}\), so the common solution is \(x\ge \frac{3}{5}\). For compound inequalities, always take the intersection.

Step 2

Why this answer is correct

The correct answer is B. \({x:x\ge \frac{3}{5}}\). Solving both parts separately gives \(x\ge \frac{3}{5}\) and \(x>-\frac{2}{3}\), so the common solution is \(x\ge \frac{3}{5}\). For compound inequalities, always take the intersection.

Step 3

Exam Tip

दोनों भाग अलग हल करने पर \(x\ge \frac{3}{5}\) और \(x>-\frac{2}{3}\) मिलते हैं, इसलिए साझा हल \(x\ge \frac{3}{5}\) है। संयुक्त असमानता में हमेशा प्रतिच्छेद लें।

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Mathematics Answer, Explanation and Revision Hints

संयुक्त असमानता (-2(3x-4)\le 5-x<2x+7) का हल क्या है? / What is the solution of the compound inequality (-2(3x-4)\le 5-x<2x+7)?

Correct Answer: B. \({x:x\ge \frac{3}{5}}\). Explanation: दोनों भाग अलग हल करने पर \(x\ge \frac{3}{5}\) और \(x>-\frac{2}{3}\) मिलते हैं, इसलिए साझा हल \(x\ge \frac{3}{5}\) है। संयुक्त असमानता में हमेशा प्रतिच्छेद लें। / Solving both parts separately gives \(x\ge \frac{3}{5}\) and \(x>-\frac{2}{3}\), so the common solution is \(x\ge \frac{3}{5}\). For compound inequalities, always take the intersection.

Which concept should I revise for this Mathematics MCQ?

Solving both parts separately gives \(x\ge \frac{3}{5}\) and \(x>-\frac{2}{3}\), so the common solution is \(x\ge \frac{3}{5}\). For compound inequalities, always take the intersection.

What exam hint can help solve this Mathematics question?

दोनों भाग अलग हल करने पर \(x\ge \frac{3}{5}\) और \(x>-\frac{2}{3}\) मिलते हैं, इसलिए साझा हल \(x\ge \frac{3}{5}\) है। संयुक्त असमानता में हमेशा प्रतिच्छेद लें।