असमानता \(\frac{2-3x}{9}<\frac{x+4}{6}\) का हल क्या है?

What is the solution of \(\frac{2-3x}{9}<\frac{x+4}{6}\)?

Explanation opens after your attempt
Correct Answer

A. \(x>-\frac{8}{15}\)

Step 1

Concept

Multiplying by (18) gives (2(2-3x)<3(x+4)). Thus (4-6x<3x+12), so \(x>-\frac{8}{9}\).

Step 2

Why this answer is correct

The correct answer is A. \(x>-\frac{8}{15}\). Multiplying by (18) gives (2(2-3x)<3(x+4)). Thus (4-6x<3x+12), so \(x>-\frac{8}{9}\).

Step 3

Exam Tip

(18) से गुणा करने पर (2(2-3x)<3(x+4)) मिलता है। इससे (4-6x<3x+12), इसलिए \(x>-\frac{8}{9}\)।

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Mathematics Answer, Explanation and Revision Hints

असमानता \(\frac{2-3x}{9}<\frac{x+4}{6}\) का हल क्या है? / What is the solution of \(\frac{2-3x}{9}<\frac{x+4}{6}\)?

Correct Answer: A. \(x>-\frac{8}{15}\). Explanation: (18) से गुणा करने पर (2(2-3x)<3(x+4)) मिलता है। इससे (4-6x<3x+12), इसलिए \(x>-\frac{8}{9}\)। / Multiplying by (18) gives (2(2-3x)<3(x+4)). Thus (4-6x<3x+12), so \(x>-\frac{8}{9}\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by (18) gives (2(2-3x)<3(x+4)). Thus (4-6x<3x+12), so \(x>-\frac{8}{9}\).

What exam hint can help solve this Mathematics question?

(18) से गुणा करने पर (2(2-3x)<3(x+4)) मिलता है। इससे (4-6x<3x+12), इसलिए \(x>-\frac{8}{9}\)।