असमानता \(\frac{2-3x}{9}<\frac{x+4}{6}\) का हल क्या है?
What is the solution of \(\frac{2-3x}{9}<\frac{x+4}{6}\)?
Explanation opens after your attempt
A. \(x>-\frac{8}{15}\)
Concept
Multiplying by (18) gives (2(2-3x)<3(x+4)). Thus (4-6x<3x+12), so \(x>-\frac{8}{9}\).
Why this answer is correct
The correct answer is A. \(x>-\frac{8}{15}\). Multiplying by (18) gives (2(2-3x)<3(x+4)). Thus (4-6x<3x+12), so \(x>-\frac{8}{9}\).
Exam Tip
(18) से गुणा करने पर (2(2-3x)<3(x+4)) मिलता है। इससे (4-6x<3x+12), इसलिए \(x>-\frac{8}{9}\)।
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