असमानता \(7-2x\le x+1\) का हल क्या है?

What is the solution of \(7-2x\le x+1\)?

Explanation opens after your attempt
Correct Answer

A. \(x\ge 2\)

Step 1

Concept

From \(7-2x\le x+1\), we get \(6\le 3x\), so \(x\ge 2\). Apply the same operation to both sides while simplifying.

Step 2

Why this answer is correct

The correct answer is A. \(x\ge 2\). From \(7-2x\le x+1\), we get \(6\le 3x\), so \(x\ge 2\). Apply the same operation to both sides while simplifying.

Step 3

Exam Tip

\(7-2x\le x+1\) से \(6\le 3x\), इसलिए \(x\ge 2\) है। असमानता को सरल करते समय दोनों पक्षों पर समान क्रिया करें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

असमानता \(7-2x\le x+1\) का हल क्या है? / What is the solution of \(7-2x\le x+1\)?

Correct Answer: A. \(x\ge 2\). Explanation: \(7-2x\le x+1\) से \(6\le 3x\), इसलिए \(x\ge 2\) है। असमानता को सरल करते समय दोनों पक्षों पर समान क्रिया करें। / From \(7-2x\le x+1\), we get \(6\le 3x\), so \(x\ge 2\). Apply the same operation to both sides while simplifying.

Which concept should I revise for this Mathematics MCQ?

From \(7-2x\le x+1\), we get \(6\le 3x\), so \(x\ge 2\). Apply the same operation to both sides while simplifying.

What exam hint can help solve this Mathematics question?

\(7-2x\le x+1\) से \(6\le 3x\), इसलिए \(x\ge 2\) है। असमानता को सरल करते समय दोनों पक्षों पर समान क्रिया करें।