असमता (-2(4x-3)\geq 10) का हल कौन सा है?

What is the solution of (-2(4x-3)\geq 10)?

Explanation opens after your attempt
Correct Answer

A. \(x\leq -\frac{1}{2}\)

Step 1

Concept

Simplifying gives \(-8x+6\geq 10\), then \(-8x\geq 4\), so \(x\leq -\frac{1}{2}\). Reverse the sign when dividing by a negative coefficient.

Step 2

Why this answer is correct

The correct answer is A. \(x\leq -\frac{1}{2}\). Simplifying gives \(-8x+6\geq 10\), then \(-8x\geq 4\), so \(x\leq -\frac{1}{2}\). Reverse the sign when dividing by a negative coefficient.

Step 3

Exam Tip

सरलीकरण से \(-8x+6\geq 10\), फिर \(-8x\geq 4\) और \(x\leq -\frac{1}{2}\) मिलता है। ऋणात्मक गुणांक से भाग देते समय चिन्ह पलटें।

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Mathematics Answer, Explanation and Revision Hints

असमता (-2(4x-3)\geq 10) का हल कौन सा है? / What is the solution of (-2(4x-3)\geq 10)?

Correct Answer: A. \(x\leq -\frac{1}{2}\). Explanation: सरलीकरण से \(-8x+6\geq 10\), फिर \(-8x\geq 4\) और \(x\leq -\frac{1}{2}\) मिलता है। ऋणात्मक गुणांक से भाग देते समय चिन्ह पलटें। / Simplifying gives \(-8x+6\geq 10\), then \(-8x\geq 4\), so \(x\leq -\frac{1}{2}\). Reverse the sign when dividing by a negative coefficient.

Which concept should I revise for this Mathematics MCQ?

Simplifying gives \(-8x+6\geq 10\), then \(-8x\geq 4\), so \(x\leq -\frac{1}{2}\). Reverse the sign when dividing by a negative coefficient.

What exam hint can help solve this Mathematics question?

सरलीकरण से \(-8x+6\geq 10\), फिर \(-8x\geq 4\) और \(x\leq -\frac{1}{2}\) मिलता है। ऋणात्मक गुणांक से भाग देते समय चिन्ह पलटें।