फलन (f(x)=\frac{1}{x-2+1}) का वास्तविक प्रांत क्या है?

What is the real domain of (f(x)=\frac{1}{x-2+1})?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}\)

Step 1

Concept

\(x^2+1\) is never (0). Therefore the function is defined for every real (x).

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}\). \(x^2+1\) is never (0). Therefore the function is defined for every real (x).

Step 3

Exam Tip

\(x^2+1\) कभी (0) नहीं होता। इसलिए फलन हर वास्तविक (x) पर परिभाषित है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{1}{x-2+1}) का वास्तविक प्रांत क्या है? / What is the real domain of (f(x)=\frac{1}{x-2+1})?

Correct Answer: A. \(\mathbb{R}\). Explanation: \(x^2+1\) कभी (0) नहीं होता। इसलिए फलन हर वास्तविक (x) पर परिभाषित है। / \(x^2+1\) is never (0). Therefore the function is defined for every real (x).

Which concept should I revise for this Mathematics MCQ?

\(x^2+1\) is never (0). Therefore the function is defined for every real (x).

What exam hint can help solve this Mathematics question?

\(x^2+1\) कभी (0) नहीं होता। इसलिए फलन हर वास्तविक (x) पर परिभाषित है।