फलन (f(x)=x-2+4) का परिसर क्या है?

What is the range of (f(x)=x-2+4)?

Explanation opens after your attempt
Correct Answer

A. \([4,\infty\))

Step 1

Concept

Since \(x^2 \ge 0\), \(x^2+4 \ge 4\). Hence the range is \([4,\infty\)).

Step 2

Why this answer is correct

The correct answer is A. \([4,\infty\)). Since \(x^2 \ge 0\), \(x^2+4 \ge 4\). Hence the range is \([4,\infty\)).

Step 3

Exam Tip

क्योंकि \(x^2 \ge 0\), इसलिए \(x^2+4 \ge 4\) है। अतः परिसर \([4,\infty\)) है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=x-2+4) का परिसर क्या है? / What is the range of (f(x)=x-2+4)?

Correct Answer: A. \([4,\infty\)). Explanation: क्योंकि \(x^2 \ge 0\), इसलिए \(x^2+4 \ge 4\) है। अतः परिसर \([4,\infty\)) है। / Since \(x^2 \ge 0\), \(x^2+4 \ge 4\). Hence the range is \([4,\infty\)).

Which concept should I revise for this Mathematics MCQ?

Since \(x^2 \ge 0\), \(x^2+4 \ge 4\). Hence the range is \([4,\infty\)).

What exam hint can help solve this Mathematics question?

क्योंकि \(x^2 \ge 0\), इसलिए \(x^2+4 \ge 4\) है। अतः परिसर \([4,\infty\)) है।