फलन (f(x)=x-2+1) का परिसर क्या है जब \(x \in \mathbb{R}\)?
What is the range of (f(x)=x-2+1) when \(x \in \mathbb{R}\)?
Explanation opens after your attempt
Correct Answer
A. \([1,\infty\))
Concept
Since \(x^2 \ge 0\), we have \(x^2+1 \ge 1\). The minimum value is (1).
Why this answer is correct
The correct answer is A. \([1,\infty\)). Since \(x^2 \ge 0\), we have \(x^2+1 \ge 1\). The minimum value is (1).
Exam Tip
क्योंकि \(x^2 \ge 0\), इसलिए \(x^2+1 \ge 1\) है। न्यूनतम मान (1) पर मिलता है।
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