फलन (f(x)=\sqrt{x+9}-4) की रेंज क्या है?
What is the range of (f(x)=\sqrt{x+9}-4)?
Explanation opens after your attempt
Correct Answer
A. \([-4,\infty\))
Concept
\(\sqrt{x+9}\ge0\), so \(\sqrt{x+9}-4\ge-4\). In exams apply the vertical shift to the basic square-root range.
Why this answer is correct
The correct answer is A. \([-4,\infty\)). \(\sqrt{x+9}\ge0\), so \(\sqrt{x+9}-4\ge-4\). In exams apply the vertical shift to the basic square-root range.
Exam Tip
\(\sqrt{x+9}\ge0\), इसलिए \(\sqrt{x+9}-4\ge-4\)। परीक्षा में वर्गमूल की basic range पर vertical shift लगाएं।
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