फलन (f(x)=\sqrt{x+12}-7) की रेंज क्या है?
What is the range of (f(x)=\sqrt{x+12}-7)?
Explanation opens after your attempt
Correct Answer
A. \([-7,\infty\))
Concept
\(\sqrt{x+12}\ge0\), so (f(x)\ge-7). In exams an outside subtraction shifts the square-root range downward.
Why this answer is correct
The correct answer is A. \([-7,\infty\)). \(\sqrt{x+12}\ge0\), so (f(x)\ge-7). In exams an outside subtraction shifts the square-root range downward.
Exam Tip
\(\sqrt{x+12}\ge0\), इसलिए (f(x)\ge-7)। परीक्षा में बाहर घटाई गई संख्या वर्गमूल की रेंज को नीचे shift करती है।
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