फलन (f(x)=\frac{x}{\sqrt{x-2+1}}) का परिसर क्या है?
What is the range of (f(x)=\frac{x}{\sqrt{x-2+1}})?
Explanation opens after your attempt
A. ((-1,1))
Concept
The denominator is always greater than (|x|), so (-1<f(x)<1). The values (-1) and (1) are only limiting values.
Why this answer is correct
The correct answer is A. ((-1,1)). The denominator is always greater than (|x|), so (-1<f(x)<1). The values (-1) and (1) are only limiting values.
Exam Tip
हर हमेशा (|x|) से बड़ा होता है, इसलिए (-1<f(x)<1)। (-1) और (1) केवल सीमा मान हैं।
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