फलन (f(x)=\frac{x-2-1}{x-2+1}) का परिसर क्या है?
What is the range of (f(x)=\frac{x-2-1}{x-2+1})?
Explanation opens after your attempt
Correct Answer
A. ([-1,1))
Concept
Let \(t=x^2\ge 0\), then \(f=\frac{t-1}{t+1}\). At (t=0), (-1) occurs and (1) is not attained.
Why this answer is correct
The correct answer is A. ([-1,1)). Let \(t=x^2\ge 0\), then \(f=\frac{t-1}{t+1}\). At (t=0), (-1) occurs and (1) is not attained.
Exam Tip
मान लें \(t=x^2\ge 0\), तब \(f=\frac{t-1}{t+1}\)। (t=0) पर (-1) मिलता है और (1) प्राप्त नहीं होता।
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