फलन (f(x)=\frac{1}{x-2+1}) की रेंज क्या है?

What is the range of (f(x)=\frac{1}{x-2+1})?

Explanation opens after your attempt
Correct Answer

A. ( (0,1])

Step 1

Concept

The denominator \(x^2+1\) has minimum value (1), so the maximum output is (1) and (0) is not reached. In exams (0) may be a limit, not a value, for reciprocals.

Step 2

Why this answer is correct

The correct answer is A. ( (0,1]). The denominator \(x^2+1\) has minimum value (1), so the maximum output is (1) and (0) is not reached. In exams (0) may be a limit, not a value, for reciprocals.

Step 3

Exam Tip

हर \(x^2+1\) की न्यूनतम वैल्यू (1) है, इसलिए अधिकतम आउटपुट (1) है और (0) नहीं मिलता। परीक्षा में reciprocal में (0) सीमा हो सकता है, वैल्यू नहीं।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{1}{x-2+1}) की रेंज क्या है? / What is the range of (f(x)=\frac{1}{x-2+1})?

Correct Answer: A. ( (0,1]). Explanation: हर \(x^2+1\) की न्यूनतम वैल्यू (1) है, इसलिए अधिकतम आउटपुट (1) है और (0) नहीं मिलता। परीक्षा में reciprocal में (0) सीमा हो सकता है, वैल्यू नहीं। / The denominator \(x^2+1\) has minimum value (1), so the maximum output is (1) and (0) is not reached. In exams (0) may be a limit, not a value, for reciprocals.

Which concept should I revise for this Mathematics MCQ?

The denominator \(x^2+1\) has minimum value (1), so the maximum output is (1) and (0) is not reached. In exams (0) may be a limit, not a value, for reciprocals.

What exam hint can help solve this Mathematics question?

हर \(x^2+1\) की न्यूनतम वैल्यू (1) है, इसलिए अधिकतम आउटपुट (1) है और (0) नहीं मिलता। परीक्षा में reciprocal में (0) सीमा हो सकता है, वैल्यू नहीं।